35b^2-80=-120b

Solution for 35b^2-80=-120b equation:

35b^2-80=-120b

We move all terms to the left:

35b^2-80-(-120b)=0

We get rid of parentheses

35b^2+120b-80=0

a = 35; b = 120; c = -80;
Δ = b2-4ac
Δ = 1202-4·35·(-80)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-160}{2*35}=\frac{-280}{70}
=-4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+160}{2*35}=\frac{40}{70}
=4/7
$